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Maintaining spaces after punctuation
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@ -92,16 +92,13 @@ def split_into_sentences(text: str) -> list[str]:
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return sentences
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def split_sentence_into_lines(sentence, offset, pixelsPerChar, pixelsInLine, lang):
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# If we can optimize this to remove the spaces, it could save a few bytes.
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splitChars = [' ']
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outStr = ""
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currLine = ""
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lineCount = 0
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currWordIndex = 0
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lineLength = 0
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spaceLength = 0
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for char in splitChars:
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sentence = sentence.replace(char, " ")
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words = sentence.split()
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@ -152,8 +149,13 @@ def split_sentence_into_lines(sentence, offset, pixelsPerChar, pixelsInLine, lan
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# Test if adding the word will go over our alloted space
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elif ((wordLength + lineLength + offset) <= pixelsInLine):
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# If not, add the word and increase the index
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currLine += (word + " ")
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lineLength += (wordLength + spaceLength)
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if (currWordIndex == (len(words) - 1)):
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# Don't add a space to the end of the sentence.
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currLine += word
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lineLength += wordLength
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else:
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currLine += (word + " ")
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lineLength += (wordLength + spaceLength)
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currWordIndex += 1
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# We need to move to the next line
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@ -181,7 +183,8 @@ def convert_char_to_byte(incoming, array, lang):
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if str(val) == chr(incoming):
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return index
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index += 1
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log_warning_error(lang, "Error", f"No match found for char [ {chr(incoming)} ]!")
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if chr(incoming) != '_':
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log_warning_error(lang, "Error", f"No match found for char [ {chr(incoming)} ]!")
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return 0
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def log_warning_error(lang, type, text):
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@ -221,6 +224,12 @@ def convert_item(ogDict, lang):
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line = line.replace(pair[0], escapeString)
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#print(line)
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# Change all the punctuation marks followed by spaces into being followed by _ .
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# These will end up being replaced by spaces anyway in the end (but ignore the error)
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puncts = ['.']
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for punct in puncts:
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line = line.replace(punct + " ", punct + "_")
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split_sents = split_into_sentences(line)
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index = 0
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outStr = ""
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