Leahnaya/FModel
1
0
Fork 0
mirror of https://github.com/4sval/FModel.git synced 2026-03-23 02:04:26 -05:00
Code Issues Actions Packages Projects Releases Wiki Activity

Fix output pose layer detection to use AdditionalProperties["Name"] instead of node.Name

Browse Source 
The root node's meaningful identifier "AnimGraph" is stored in the
struct's "Name" property (AdditionalProperties["Name"]), not the
node's generated Name field (e.g. "AnimGraphNode_Root_0").

Co-authored-by: LoogLong <86428208+LoogLong@users.noreply.github.com>
This commit is contained in:
copilot-swe-agent[bot] 2026-03-02 06:42:01 +00:00
parent c1962c77be
commit 84df34b4dc
2 changed files with 8 additions and 4 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

6
FModel/ViewModels/AnimGraphViewModel.cs
View File

@ -215,9 +215,11 @@ public class AnimGraphViewModel
/// </summary>
private static string GetLayerName(List<AnimGraphNode> nodes, int index)
{
// The final output pose layer contains an AnimGraphNode_Root with Name="AnimGraph"
// The final output pose layer contains an AnimGraphNode_Root whose
// "Name" property (in AdditionalProperties) is set to "AnimGraph"
var rootNode = nodes.FirstOrDefault(n =>
n.Name.Equals("AnimGraph", StringComparison.OrdinalIgnoreCase));
n.AdditionalProperties.TryGetValue("Name", out var name) &&
name.Equals("AnimGraph", StringComparison.OrdinalIgnoreCase));
if (rootNode != null)
return "AnimGraph";

6
FModel/Views/AnimGraphViewer.xaml.cs
View File

@ -68,9 +68,11 @@ public partial class AnimGraphViewer
return;
// Show only the final output pose layer (AnimGraph) initially.
// The root node of the output layer is an AnimGraphNode_Root with Name="AnimGraph".
// The root node of the output layer has a "Name" property set to "AnimGraph"
// in its AdditionalProperties (from the AnimGraphNode_Root struct).
var outputLayer = _viewModel.Layers.FirstOrDefault(l =>
l.Nodes.Any(n => n.Name.Equals("AnimGraph", StringComparison.OrdinalIgnoreCase)))
l.Nodes.Any(n => n.AdditionalProperties.TryGetValue("Name", out var name) &&
name.Equals("AnimGraph", StringComparison.OrdinalIgnoreCase)))
?? _viewModel.Layers[0];
var layersToShow = new[] { outputLayer };